通过它的方法名称连接到一个类方法在Python中的for循环中的一个var

Question

我将PyQt4中的一些按钮连接到相同的函数中，该函数将查找之间的匹配按钮名称或标题和类别实例方法名称管理不同的操作。

我正在以不同的方式将类instance methods放到列表中，迭代并尝试将其各自的函数连接到它的按钮。但我无法以任何方式使方法callback()工作。

############################################## 
# Operatios RIG class INSTANCE 
# 
self.OperationsRig = OperationsFile.Operations() 
#### BUTTONS TO CONNECT -----------------------# 

mirrorButton.clicked.connect(self.operations_module) 
flipButton.clicked.connect(self.operations_module) 
resetButton.clicked.connect(self.operations_module) 
visibilityButton.clicked.connect(self.operations_module) 

def operations_module(self): 
    # Text gives me the name to Match ------------------# 
    text = self.sender().text() 
    # ------------------------# 
    # have 3 ways of getting the class instance methods into a list to iterate .. 
    method_list = [func for func in dir(self.OperationsRig) if callable(getattr(self.OperationsRig, func))] 
    methods = vars(self.OperationsRig.__class__).items() 
    member =inspect.getmembers(self.OperationsRig, predicate=inspect.ismethod) 

    # This var is a list to pass to the Method 
    Sel_list = cmds.ls(sl=True) 

    # iterate over the "self.OperationsRig" methods 
    # 
    """ option 1 """ 
    for meth in method_list: 
     if text.strip().lower() in meth.lower()[:]: 
      # if match, and it does, will call the class method and send the data. 
      pass 
      #getattr(self.OperationsRig,meth)(Sel_list) # Executes the funcion instance, but is not 
                 # sending the data, I've checked printing inside. 
                 # NoneTypeObject is not iterable. no data sent. 

    """ option 2 """ 
    for meth in methods: 
     if text.strip().lower() in meth[0].lower()[:]: 
      pass 
      # if match, and it does, will call the class method and send the data. 
      #method = meth[1] # Gets the memory address of the function. Good. 
      #method(Sel_list) # Does not return anything, the process of the funcion gets an 
           # error at the very beggining of the method process 

    """ option 3 """ 
    for meth in member: 
     if text.strip().lower() in meth[0].lower()[:]: 
      meth[1](Sel_list) # Gets the memory address of the function. Good. as a bound method 
           # Same result as option 1 - # NoneTypeObject is not iterable. no data sent. 
# --------------------------------------------------------------------------------------------------# 

匹配进行得很好，问题在于调用函数。什么即时做错了？

Answer 1

我不知道OperationsRig类的定义，所以我自己定义一个。

既然它可以成功匹配，我认为这不是pyqt的问题。

这里是我的代码：

class OperationsRig: 
    def foo(self, msg): 
     print('foo:' + str(msg)) 
     return 'foo OK' 

    def foo1(self, msg): 
     print('foo1:' + str(msg)) 
     return 'foo1 OK' 


opr = OperationsRig() 

def operations_module(text): 
    # Text gives me the name to Match ------------------# 
    # ------------------------# 
    # have 3 ways of getting the class instance methods into a list to iterate .. 
    method_list = [func for func in dir(opr) if callable(getattr(opr, func))] 

    # This var is a list to pass to the Method 
    Sel_list = [1,2,3] 

    # iterate over the "self.OperationsRig" methods 
    # 
    """ option 1 """ 
    for meth in method_list: 
     if text.strip().lower() in meth.lower()[:]: 
      # if match, and it does, will call the class method and send the data. 
      pass 
      return getattr(opr, meth)(Sel_list) # Executes the funcion instance, but is not 
                 # sending the data, I've checked printing inside. 
                 # NoneTypeObject is not iterable. no data sent. 
print(operations_module('foo')) 
print(operations_module('foo1')) 

这是结果：

foo:[1, 2, 3] 
foo OK 
foo1:[1, 2, 3] 
foo1 OK 

Process finished with exit code 0 

它运行作为我的期望，我还是不能，为什么你的代码失败搞清楚。或者，如果你可以进一步解释。