R - 如何重新整理两列中的数据帧整理值?

问题描述:

我有一个数据框,我需要重塑,以方便它在一个viz应用程序中使用。这里的数据帧的压缩版本:R - 如何重新整理两列中的数据帧整理值?

Carrier <- c("Mesa", "United", "JetBlue", "ExpressJet", "SkyWest") 
Flight_Num <- c(7124, 7177, 334, 1223, 6380) 
Origin <- c("ORD", "EWR", "SFO", "BOS", "BDL") 
Dest <- c("PIT", "BOI", "DSM", "CWA", "CMH") 
Sched_Depr <- c(1955, 1900, 1845, 1253, 1755) 

df <- data.frame(Carrier, Flight_Num, Origin, Dest, Sched_Depr) 

    Carrier Flight_Num Origin Dest Sched_Depr 
1  Mesa  7124 ORD PIT  1955 
2  United  7177 EWR BOI  1900 
3 JetBlue  334 SFO DSM  1845 
4 ExpressJet  1223 BOS CWA  1253 
5 SkyWest  6380 BDL CMH  1755 

OriginDept被解释为地理数据(即坐标)由应用程序即。我需要将它们整理在一个名为Coords的列中。同时我需要创建一个新的订单标记变量Order_Points。因此,新的,重塑数据帧应该是这样的:

 Carrier Flight_Num Coords Sched_Depr Order_Points 
1  Mesa  7124 ORD  1955   1 
2  Mesa  7124 PIT  1955   2 
3  United  7177 EWR  1900   1 
4  United  7177 BOI  1900   2 
5  JetBlue  334 SFO  1845   1 
6  JetBlue  334 DSM  1845   2 
7 ExpressJet  1223 BOS  1253   1 
8 ExpressJet  1223 CWA  1253   2 
9  SkyWest  6380 BDL  1755   1 
10 SkyWest  6380 CMH  1755   2 

什么是整理两列这样一种有效的方式,同时保持(和复制)其他变量?

这里有一个选项使用tidyverse函数。我们使用gather将数据帧从“宽”格式转换为“长格式”。这还添加了一个列(在此称为Type),标记CoordsOrigin还是Dest

library(tidyverse) 

df.long = df %>% 
    gather(Type, Coords, Origin, Dest) %>% 
    arrange(Carrier, desc(Type)) 
 Carrier Flight_Num Sched_Depr Type Coords 
1 ExpressJet  1223  1253 Origin BOS 
2 ExpressJet  1223  1253 Dest CWA 
3  JetBlue  334  1845 Origin SFO 
4  JetBlue  334  1845 Dest DSM 
5  Mesa  7124  1955 Origin ORD 
6  Mesa  7124  1955 Dest PIT 
7  SkyWest  6380  1755 Origin BDL 
8  SkyWest  6380  1755 Dest CMH 
9  United  7177  1900 Origin EWR 
10  United  7177  1900 Dest BOI 
+0

轻微的一个改进:'df%>% 聚集(Order_Points,Coords,Origin,Dest)%>% mutate(Order_Points => ifelse(Order_Points ==“Origin”,1,2))%>% select(Carrier,Flight_Num,Coords,Sched_Depr,Order_Points)%>% arrange(desc(Sched_Depr))' – jsb

您还可以使用基础R:

dat <- data.frame(Carrier, Flight_Num, Origin, Dest, Sched_Depr) 
    df=reshape(dat,idvar = "Carrier",varying = list(3:4),direction = "long") 
`row.names<-`(df[order(df[,1]),],NULL) 
     Carrier Flight_Num Sched_Depr time Origin 
1 ExpressJet  1223  1253 1 BOS 
2 ExpressJet  1223  1253 2 CWA 
3  JetBlue  334  1845 1 SFO 
4  JetBlue  334  1845 2 DSM 
5  Mesa  7124  1955 1 ORD 
6  Mesa  7124  1955 2 PIT 
7  SkyWest  6380  1755 1 BDL 
8  SkyWest  6380  1755 2 CMH 
9  United  7177  1900 1 EWR 
10  United  7177  1900 2 BOI 

可以时间变量名称更改为你喜欢在你上面的例子