分页符后出现Reportlab错误
问题描述:
我正在设计一个双面打印双面打印。之后,我添加分页符,我得到以下错误:分页符后出现Reportlab错误
File "f:\Dropbox\pms\pms_reports.py", line 450, in <module>
a = Key_card1()
File "f:\Dropbox\pms\pms_reports.py", line 441, in __init__
doc.build(elements)
File "c:\Python34\Lib\site-packages\reportlab\platypus\doctemplate.py", line 1171, in build
BaseDocTemplate.build(self,flowables, canvasmaker=canvasmaker)
File "c:\Python34\Lib\site-packages\reportlab\platypus\doctemplate.py", line 927, in build
self.handle_flowable(flowables)
File "c:\Python34\Lib\site-packages\reportlab\platypus\doctemplate.py", line 775, in handle_flowable
self.handle_keepWithNext(flowables)
File "c:\Python34\Lib\site-packages\reportlab\platypus\doctemplate.py", line 742, in handle_keepWithNext
while i<n and flowables[i].getKeepWithNext(): i += 1
builtins.TypeError: getKeepWithNext() missing 1 required positional argument: 'self'
这里是我的代码:
from reportlab.lib.pagesizes import A4, landscape
from reportlab.platypus import SimpleDocTemplate, Table, TableStyle, Paragraph, PageBreak
from reportlab.lib.styles import getSampleStyleSheet
class Key_card1():
def __init__(self, start_date=datetime.now(), room="1",
end_date=datetime.now()+timedelta(days=1), password = "999999"):
stylesheet = getSampleStyleSheet()
doc = SimpleDocTemplate("key_card.pdf", pagesize=A4)
if password == "999999":
password = str(random.randint(10000,99999))
roomno = "Room" + room
w_text = []
w_text.append(Paragraph("To use the wireless broadband…:",stylesheet["BodyText"]))
w_text.append(Paragraph("User id: <b>" + roomno + "</b>", stylesheet["BodyText"]))
w_text.append(Paragraph("Password: <b>" + password + "</b>", stylesheet["BodyText"]))
message_text = []
message_text.append(Paragraph("Our current menus ...", stylesheet["BodyText"]))
message_text.append(Paragraph("Our restaurant can get very busy ...",stylesheet["BodyText"]))
message_text.append(Paragraph("Your shower has a safety device to...", stylesheet["BodyText"]))
message_text .append(Paragraph("Please do not hesitate to call...",stylesheet["BodyText"]))
elements=[]
table_data = [(w_text, message_text)]
the_table = Table(table_data)
the_table.setStyle(TableStyle([('VALIGN',(0,0),(-1,-1),'MIDDLE')]))
elements.append(the_table)
elements.append(PageBreak)
#Cover page
logo= "y:\marketing\priory_master_logo bw.jpg"
im = Image(logo, 3*cm, 1.258*cm)
cover_data = []
cover_data.append(im)
cover_data.append(Paragraph("Room number : " + room, stylesheet["BodyText"]))
left_cell =[]
left_cell.append(Paragraph(" ", stylesheet["BodyText"]))
table_data1 = [(left_cell, cover_data)]
the_table1 = Table(table_data1)
the_table1.setStyle(TableStyle([('VALIGN',(0,0),(-1,-1),'MIDDLE')]))
elements.append(the_table1)
doc.build(elements)
我试图修改ReportLab的模块,但我没有成功。任何人有任何想法?
答
我试图理解错误,我猜这里有问题 doc = SimpleDocTemplate("key_card.pdf", pagesize=A4)
。问题可能是参数“key_card.pdf”。我不知道
编辑:也许,BaseDocTemplate.build(self,flowables, canvasmaker=canvasmaker)
问题是关于它连接到doc.build元素(元素)
解决方案“悬浮剂”的说法 - > elements.append(分页符)应该是元素。附加(PageBreak())
我转换了代码创建一个pageTemplate和框架和使用BaseDocTemplate并得到完全相同的错误。当我将分页符注释掉时,它全部打印出来没有错误(除非没有分页符)。 – Dkellygb
我想我发现它'elements.append(PageBreak)'应该是'elements.append(PageBreak())'。我谷歌搜索“缺少1所需的位置参数:'自我'”,并发现这些[链接](http://*.com/questions/17534345/typeerror-missing-1-required-positional-argument-self)[链接]( http://*.com/questions/37289391/missing-1-required-positional-argumentself-when-assigning-a-method-to-a-varia)你应该注意类初始化;) –
你是绝对正确的。我不知道为什么我没有看到它。如果你让你的评论成为答案,我会接受它。 - 谢谢! – Dkellygb