从列表中删除包含某些数据的对象

Question

我们都知道我们可以将大量数据类型插入到python列表中。例如。人物

X=['a','b','c'] 

的列表中删除“C”所有我需要做的就是

X.remove('c') 

现在我需要的是删除包含特定字符串的对象。

class strng: 
    ch = '' 
    i = 0 
X = [('a',0),('b',0),('c',0)]    #<---- Assume The class is stored like this although it will be actually stored as object references 
Object = strng() 
Object.ch = 'c' 
Object.i = 1 
X.remove('c')     #<-------- Basically I want to remove the Object containing ch = 'c' only. 
           #   variable i does not play any role in the removal 
print (X) 

答案我想：

[('a',0),('b',0)]     #<---- Again Assume that it can output like this 

Answer 1

我想你想要的是这样的：

>>> class MyObject: 
... def __init__(self, i, j): 
...  self.i = i 
...  self.j = j 
... def __repr__(self): 
...  return '{} - {}'.format(self.i, self.j) 
... 
>>> x = [MyObject(1, 'c'), MyObject(2, 'd'), MyObject(3, 'e')] 
>>> remove = 'c' 
>>> [z for z in x if getattr(z, 'j') != remove] 
[2 - d, 3 - e] 

Answer 2

对于列表

X = [('a',0),('b',0),('c',0)] 

如果你知道一个元组的第一项始终是一个字符串，并且要删除该字符串如果它具有不同的值，则使用列表理解：

X = [('a',0),('b',0),('c',0)] 

X = [(i,j) for i, j in X if i != 'c'] 

print (X) 

个输出如下：

[('a', 0), ('b', 0)] 

Answer 3

下列功能就会到位删除所有项目对他们的条件是True：

def remove(list,condtion): 
    ii = 0 
    while ii < len(list): 
     if condtion(list[ii]): 
      list.pop(ii) 
      continue   
     ii += 1 

这里如何使用它：

class Thing: 
    def __init__(self,ch,ii): 
     self.ch = ch 
     self.ii = ii 
    def __repr__(self): 
     return '({0},{1})'.format(self.ch,self.ii) 

things = [ Thing('a',0), Thing('b',0) , Thing('a',1), Thing('b',1)]  
print('Before ==> {0}'.format(things))   # Before ==> [(a,0), (b,0), (a,1), (b,1)] 
remove(things , lambda item : item.ch == 'b') 
print('After ==> {0}'.format(things))   # After ==> [(a,0), (a,1)]