右键单击Java中的Swing节点添加JPopup菜单

Question

在GUI中，我在JPanel的左侧显示一个JTree。现在对于每个Node(leaf)，在鼠标右键单击上，我想要显示JPopup菜单，要求在右边的JPanel中显示有关Node的统计信息。

由于我是新的摆动，任何人都可以帮助代码。 在此先感谢。

Regards， Tushar Dodia。

Answer 1

使用的JTree的方法

public TreePath getPathForLocation(int x, int y) 

随后的TreePath

public Object getLastPathComponent() 

返回从点所需的节点，在用户右键点击。

Answer 2

似乎已经引起了一些混乱（混淆自己;-) - 所以这里做的componentPopup

JPopupMenu popup = new JPopupMenu(); 
    final Action action = new AbstractAction("empty") { 

     @Override 
     public void actionPerformed(ActionEvent e) { 
      // TODO Auto-generated method stub 
     } 
    }; 
    popup.add(action); 
    JTree tree = new JTree() { 

     /** 
     * @inherited <p> 
     */ 
     @Override 
     public Point getPopupLocation(MouseEvent e) { 
      if (e != null) { 
       TreePath path = getClosestPathForLocation(e.getX(), e.getY()); 
       action.putValue(Action.NAME, String.valueOf(path.getLastPathComponent())); 
       return e.getPoint(); 
      } 
      action.putValue(Action.NAME, "no mouse"); 
      return null; 
     } 

    }; 
    tree.setComponentPopupMenu(popup); 

Answer 3

我把@kleopatra解决方案，改变了它稍微的目标位置相关的配置代码段。 也许这不是最好的方式，但为我工作。

JTree tree = new JTree() { 
    private static final long serialVersionUID = 1L; 
    @Override public Point getPopupLocation(MouseEvent e) { 
     if (e == null) return new Point(0,0); 
     TreePath path = getClosestPathForLocation(e.getX(), e.getY()); 
     Object selected = path != null ? path.getLastPathComponent() : null; 
     setComponentPopupMenu(getMenuForTreeNode(getComponentPopupMenu(), selected)); 
     setSelectionPath(path); 
     return e.getPoint(); 
    } 
}; 



public JPopupMenu getMenuForTreeNode(JPopupMenu menu, Object treeNode) { 
    if (menu == null) menu = new JPopupMenu("Menu:"); 
    menu.removeAll(); 
    if (treeNode instanceof MyTreeItem) { 
     menu.add(new JMenuItem("This is my tree item: " + treeNode.toString())); 
    } 
    return menu; 
}