foreach循环工作只在数据库的第一个记录在php中
问题描述:
我被困在我的代码中的一个条件。我正在从PHP发送gcm推送通知给多个用户。我从数据库中获得注册ID。在代码中,我使用foreach循环发送通知。但我不知道为什么它只发送推送通知给一个用户而不是全部用户。如果我删除推送通知代码,那么它会显示数据库中的所有注册ID。foreach循环工作只在数据库的第一个记录在php中
<?php
$host_name = "localhost";
$user_name = "xxxxxxx";
$user_pass = "xxxxx";
$db_name = "xxxxxx";
$conn=mysql_connect($host_name,$user_name,$user_pass);
if(!$conn) {
echo"could not connect:".mysql_error();
} else {
mysql_select_db($db_name,$conn);
}
$query = "select reg_id from property_register where reg_id != ''";
$result = mysql_query($query) or die(mysql_error());
foreach(mysql_fetch_array($result) as $r_id) {
$gcmRegID = $r_id[0];
echo $gcmRegID . "<br>";
$pushMessage = "New Property Posted in CPO";
if (isset($gcmRegID) && isset($pushMessage)) {
$gcmRegIds = array($gcmRegID);
$message = array("m" => $pushMessage);
$url = 'https://android.googleapis.com/gcm/send';
$fields = array(
'registration_ids' => $gcmRegIds,
'data' => $message,
);
// Update your Google Cloud Messaging API Key
define("GOOGLE_API_KEY", "xxxxxxxxxxxxxxxxxxxxxxxxxxxx");
$headers = array(
'Authorization: key=' . GOOGLE_API_KEY,
'Content-Type: application/json'
);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($fields));
$result = curl_exec($ch);
if ($result === FALSE) {
die('Curl failed: ' . curl_error($ch));
}
curl_close($ch);
return $result;
}
}
?>
总之,foreach循环只向第一个用户发送通知,而不是全部。如果我删除GCM代码,做foreach循环的回声记录它的显示我的所有
感谢
答
您的foreach循环返回,这将导致第一次通过的foreach火的retrun呼叫,从来没有通过另一个foreach循环。回报是不需要的。改用下面的代码。
<?php
$host_name = "localhost";
$user_name = "xxxxxxx";
$user_pass = "xxxxx";
$db_name = "xxxxxx";
$conn=mysql_connect($host_name,$user_name,$user_pass);
if(!$conn) {
echo"could not connect:".mysql_error();
} else {
mysql_select_db($db_name,$conn);
}
$query = "select reg_id from property_register where reg_id != ''";
$result = mysql_query($query) or die(mysql_error());
foreach(mysql_fetch_array($result) as $r_id) {
$gcmRegID = $r_id[0];
echo $gcmRegID . "<br>";
$pushMessage = "New Property Posted in CPO";
if (isset($gcmRegID) && isset($pushMessage)) {
$gcmRegIds = array($gcmRegID);
$message = array("m" => $pushMessage);
$url = 'https://android.googleapis.com/gcm/send';
$fields = array(
'registration_ids' => $gcmRegIds,
'data' => $message,
);
// Update your Google Cloud Messaging API Key
define("GOOGLE_API_KEY", "xxxxxxxxxxxxxxxxxxxxxxxxxxxx");
$headers = array(
'Authorization: key=' . GOOGLE_API_KEY,
'Content-Type: application/json'
);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($fields));
$result = curl_exec($ch);
if ($result === FALSE) {
die('Curl failed: ' . curl_error($ch));
}
curl_close($ch);
}
}
?>
您正在返回。 – KiwiJuicer
是的,我知道它的要求。否则推送通知将无法正常工作..对此有何建议? @KiwiJuicer –
对不起,我不明白为什么当curl请求成功时应该这样做。它会简单地返回你的结果,无论你从哪里调用函数。 – KiwiJuicer