虽然循环偶数

Question

我的问题是以下。如果我输入数字2，则代码将其计为一个奇数。

剩余2/2 = 0，所以错误没有意义。

下面是程序：

import java.util.Scanner; 

public class Ohjelma { 

public static void main(String[] args) { 

    // Tänne voit kirjoittaa ohjelmakoodia. Ohjelmasi voit ajaa 
    // valitsemalla menusta Run->Run File tai painamalla Shift+F6 
    Scanner reader = new Scanner(System.in); 
    System.out.println("Type numbers: "); 
    int number = Integer.parseInt(reader.nextLine()); 
    int sum = 0; 
    int many = 0; 
    double average = 0; 
    int even = 0; 
    int odd = 0; 

    while (number != -1) { 
     System.out.println("Type numbers: "); 
     sum = sum + number; 
     number = Integer.parseInt(reader.nextLine()); 
     many++; 
     average = (double)sum/many; 
     if (number%2 == 0) { 
      even++; 
     } else { 
      odd++; 
     } 
    } 

    System.out.println("Thank you and see you later!"); 
    System.out.println("The sum is " + sum); 
    System.out.println("How many numbers: " + many); 
    System.out.println("Average: " + average); 
    System.out.println("Even numbers: " + even); 
    System.out.println("Odd numbers: " + odd); 

Answer 1

主要问题是，对于程序的关键部分，除了将其添加到正在运行的sum之外，它基本上忽略了第一个输入。你想重写它：

Scanner reader = new Scanner(System.in); 
int sum = 0; 
int many = 0; 
double average = 0; 
int even = 0; 
int odd = 0; 

do { 
    System.out.println("Type numbers: "); 
    number = Integer.parseInt(reader.nextLine()); 
    if (number == -1) 
     break; 
    sum = sum + number; 
    many++; 
    average = (double)sum/many; 
    if (number%2 == 0) { 
     even++; 
    } else { 
     odd++; 
    } 
} while (true); 

这将肯定处理正确的偶数和奇数。

Answer 2

你的代码读取输入的第二行到number它检查number是奇数... -1是奇数前。