MySQL列格栅计数匹配查询的单词数量？

Question

我在尝试根据查询中在该行中找到的单词数来对匹配进行评分。我盯着这样做：

SELECT Text, MATCH(`Text`) AGAINST ('$s') AS Grade 

但很快我意识到了这一点，因为Grade没有工作，是基于很多东西一样，例如订单的话，每个字的长度等。

我只想知道连续出现的单词的百分比。

EG：

$s = 'i want pizza' 
`Text` = 'pizza I want' // In this case Grade should be 100 as all words are found 

其他例子：

Text    | Grade 
pizza I want too | 100 // All words were found, It doesn't matter if there are extra words 
pizza I want  | 100 
i want   | 66 // Only 66% of the words are present 
want want want | 33 // Only 33% of the words are present 

Answer 1

$s = 'i want pizza'; 
$text = 'pizza I want'; 

//move to lower-case to ignore case-differences 
$s = strtolower($s); 
$text = strtolower($text); 

//count the number of words in $s 
$slen = count(explode(" ", $s)); 
//create an array of words from the text that we check 
$arr = explode(" ", $text); 
$count = 0; 
//go over the words from $text and count words that appear on $s 
foreach ($arr as $word) { 
    if(strpos($s, $word) !== false){ 
     $count++; 
    } 
} 
//display the percentage in format XX.XX 
echo number_format((double)(100 * $count/$slen),2);