Firebase创建用户swift不起作用
问题描述:
下面我刚才输入的错误是显示“无法覆盖类型值”(,) - > Void'to expected argument type'(NSERROR!) - > Void!)'Firebase创建用户swift不起作用
在这行代码:?什么是错的
FIREBASE_REF.createUser(email, password: password, withCompletionBlock: {(error,authData) -> Void in
@IBAction func creatAccountAction(sender: AnyObject) {
let email = self.emailTextField.text
let password = self.passwordTextField.text
if email != "" && password != ""
{
FIREBASE_REF.createUser(email, password: password, withCompletionBlock: {(error,authData) -> Void in
if error != nil {
FIREBASE_REF.authUser(email, password: password, withCompletionBlock: { (error, authData) -> Void in
if error == nil {
NSUserDefaults.standardUserDefaults().setValue(authData.uid, forKey: "uid")
}
else {
print (error)
}
})
}
else {
print (error)
}
}
)}
else
答
试试这个:
FIREBASE_REF.createUser(email, password: password, withCompletionBlock: {(error) -> Void in
此块有可能只有一个参数
答
创建用户有两种选择,一种是创建用户,如果失败返回一个错误(withCompletionBlock),另一种选项返回authData(withValueCompletionBlock):这就是你想要的。
myRootRef.createUser(email, password: pw, withValueCompletionBlock: { error, result in
if error != nil {
print("error creating user")
} else {
let uid = result["uid"] as! String
NSUserDefaults.standardUserDefaults().setValue(uid, forKey: "uid")
//pass the parameters to another function to auth the user
self.authUserWithAuthData(email, password: pw)
}
})
非常感谢! – elciann