MySQL的左用(没有行)连接条件上右表
SHOPS
+----+------------+
| id | shop_name |
+----+------------+
ORDERBOOKINGS
+-----+---------+-------------+------------+
| id | shop_id | grand_total | created_at |
+-----+---------+-------------+------------+
我希望得到像这样的表:MySQL的左用(没有行)连接条件上右表
+------------+--------------+--------------+
| shop_name | total_orders | total_amount |
+------------+--------------+--------------+
的情况是,我有日期过滤器指定之间只返回订单总额日期。我希望它返回所有商店(如果在这些日期之间没有一些商店的订单,那么它应该将total_orders作为0返回)。
注意:一些商店可能甚至没有订单表中的条目。
我曾尝试以下,但它无法从商店返回表中的所有行:
SELECT COUNT(orderbookings.id),
SUM(orderbookings.grand_total),
shops.shop_name
FROM `orderbookings`
LEFT JOIN shops
on orderbookings.shop_id = shops.id
where orderbookings.created_at BETWEEN "2015-10-22 17:02:02" AND "2017-03-07 17:02:02"
GROUP BY shops.id
任何想法,我怎么能做到这一点?
谢谢。
更换where
到and
在您的查询,LEFT JOIN
到RIGHT JOIN
:
SELECT
COUNT(orderbookings.id),
COALESCE(SUM(orderbookings.grand_total), 0),
shops.shop_name
FROM `orderbookings`
RIHGT JOIN shops on orderbookings.shop_id = shops.id and orderbookings.created_at BETWEEN "2015-10-22 17:02:02" AND "2017-03-07 17:02:02"
GROUP BY shops.id
说明:
1)如果你想获得所有的商店,你应该使用shops
作为主表,然后离开加盟orderbookings
,这里我使用正确的连接,因为你使用orderbookings
作为主表;
2)如果在where
中使用orderbookings
的列,则左连接将作为内连接。
最后,left join
解决方案将是这样的:
SELECT
COUNT(orderbookings.id),
COALESCE(SUM(orderbookings.grand_total), 0),
shops.shop_name
FROM `shops `
LEFT JOIN orderbookings on orderbookings.shop_id = shops.id and orderbookings.created_at BETWEEN "2015-10-22 17:02:02" AND "2017-03-07 17:02:02"
GROUP BY shops.id
你想扭转你的加入,并添加一些IFNULLs:
SELECT IFNULL(COUNT(orderbookings.id),0),
IFNULL(SUM(orderbookings.grand_total),0),
shops.shop_name
FROM `orderbookings`
RIGHT OUTER JOIN shops
on orderbookings.shop_id = shops.id
and orderbookings.created_at BETWEEN "2015-10-22 17:02:02" AND "2017-03-07 17:02:02"
GROUP BY shops.id
您可能需要将'WHERE'条件移至'ON'子句。 –
没有帮助。仍然只返回订单表中有订单的那些商店。离开所有其他商店。你想让我提供真实的数据吗? –
呐喊,加入语法有点生疏。尝试一个正确的外部连接。更新了答案。 – Ilion
已经尝试过。仍然只返回在订单表中有条目的商店。离开所有其他商店。 –
@ nikhil.malik更新了我的答案,请再次检查。 – Blank
现在工作。感谢名单! –