UIActivityView按钮错误
问题描述:
我正在尝试使用UIActivityView为我的应用程序创建共享按钮。当我按下应用程序中的按钮时,出现错误。代码有什么问题?UIActivityView按钮错误
@IBAction func shareButton(_ sender: UIButton) {
let texttoshare = "Sharing"
let URLtoshare = NSURL(string: "www.google.com")
let objectsToShare:NSArray = [texttoshare, URLtoshare!]
let activityVC = UIActivityViewController(activityItems: objectsToShare as! [Any], applicationActivities: nil)
self.present(activityVC, animated: true, completion: nil)
}
}
错误:是线程1:信号SIGABRT
答
试试这个。至少,它的工作对我来说没有errores ..
let texttoshare = "Sharing"
let URLtoshare = URL(string: "www.google.com")
let activityVC = UIActivityViewController(activityItems: [texttoshare, URLtoshare!], applicationActivities: nil)
self.present(activityVC, animated: true, completion: nil)
如果你想使用UIActivityViewController
为ipad公司,你需要为activityVC
指定popoverPresentationController?.sourceView
。例如:
let texttoshare = "Sharing"
let URLtoshare = URL(string: "www.google.com")
let activityVC = UIActivityViewController(activityItems: [texttoshare, URLtoshare!], applicationActivities: nil)
activityVC.popoverPresentationController?.sourceView = button...
self.present(activityVC, animated: true, completion: nil)
+0
你把什么“按钮... “?我仍然得到相同的错误 – Phillip
+0
任何你想要的...例如shareButton IBOutlet ...或者self.view,如果你愿意的话,测试几个视图,看看有什么适合你的需求...... –
请将错误添加到您的问题。 –
尝试更改'NSURL(字符串:...'到URL(字符串:...),并删除':NSArray' –
@LucianoRodríguez仍然是同样的错误... – Phillip