Swift 3如何解析数据
问题描述:
我的Swift 3代码有一个基金会Data字节集合(从SQlite BLOB读取)。数据的内部内容具有以下结构的多个块:Swift 3如何解析数据
{
UINT32 count; // number of points in this trkseg
UINT32 colour; // RGB colour of the line drawn for this trkseq
Double lat; // latitude of 1st point
Double long; // longitude of 1st point
Coord point[count-1] // array of points (2nd to last points)
}
typedef struct {
Float lat // difference in latitude of this point from the lat of the 1st point
Float long // difference in longitude of this point from the lat of the 1st point
} Coord;
这很容易在C和Java中解析。不幸的是,我不能找出用Swift 3解析这个问题的最佳方法。我不是问如何解析这个确切的数据布局,而仅仅是为了解析Swift 3中的这些原始数据的建议和最佳实践。从网络搜索和Apple文档我很遗憾!
***答案 - 感谢Martin R让我走上正轨。我在这里添加一些代码来展示我如何解决这个问题,以防止它帮助其他人。正如马丁所说,有很多方法可以解决这个问题。我的解决方案可以确保无论主机字节顺序如何,blob数据都将正确解析,而网络endian顺序(大端)将始终正确解析。
/// Parse the SQLite data blob to add GPS track segments
///
/// - Parameter data: GPS track information
private func addTracks(_ data: Data) {
// The data holds compressed GPX data. It has multiple track segments.
// It has a block of binary data per track segment with this structure:
// {
// UINT32 count; // number of points in this trkseg
// UINT32 colour; // RGB colour of the line drawn for this trkseq
// Double lat; // latitude of 1st point
// Double long; // longitude of 1st point
// Coord point[count-1] // array of points (2nd to last points)
// }
//
// typedef struct {
// Float lat // difference in latitude of this point from the lat of the 1st point
// Float long // difference in longitude of this point from the lat of the 1st point
// } Coord;
var dataCount = data.count // number of data bytes
var pointCount = 0 // counts coordinates per trkseg
var colour:UInt = 0
var lat:Double = 0.0
var long:Double = 0.0
var bigEndian = true
var i = 0
// From http://codereview.stackexchange.com/questions/114730/type-to-byte-array-conversion-in-swift
if (NSHostByteOrder() == NS_LittleEndian) {
bigEndian = false
}
while (dataCount >= 40) {
pointCount = Int(self.uint32Value(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
if (pointCount < 2 || ((pointCount-1)*8 + 24 > dataCount)) {
print("ERROR, pointCount=\(pointCount)")
break
}
colour = UInt(self.uint32Value(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
let firstLat = self.doubleValue(data: data.subdata(in: i..<i+8), isBigEndian: bigEndian)
i = i+8
let firstLong = self.doubleValue(data: data.subdata(in: i..<i+8), isBigEndian: bigEndian)
i = i+8
print("pointCount=\(pointCount) colour=\(colour) firstLat=\(firstLat) firstLong=\(firstLong)")
for _ in 1..<pointCount {
lat = firstLat - Double(self.floatValue(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
long = firstLong - Double(self.floatValue(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
print("lat=\(lat) long=\(long)")
}
dataCount = dataCount - 24 - (pointCount-1)*8;
}
}
private func floatValue(data: Data, isBigEndian: Bool) -> Float {
if (isBigEndian) {
return Float(bitPattern: UInt32(littleEndian: data.withUnsafeBytes { $0.pointee }))
}
else {
return Float(bitPattern: UInt32(bigEndian: data.withUnsafeBytes { $0.pointee }))
}
}
private func doubleValue(data: Data, isBigEndian: Bool) -> Double {
if (isBigEndian) {
return Double(bitPattern: UInt64(littleEndian: data.withUnsafeBytes { $0.pointee }))
}
else {
return Double(bitPattern: UInt64(bigEndian: data.withUnsafeBytes { $0.pointee }))
}
}
private func uint32Value(data: Data, isBigEndian: Bool) -> UInt32 {
if (isBigEndian) {
return data.withUnsafeBytes{ $0.pointee }
}
else {
let temp: UInt32 = data.withUnsafeBytes{ $0.pointee }
return temp.bigEndian
}
}
答
一种可能的方法是使用
public func withUnsafeBytes<ResultType, ContentType>(_ body: (UnsafePointer<ContentType>) throws -> ResultType) rethrows -> ResultType
方法来访问和取消引用在所述数据中的字节。 占位类型ContentType
可以从上下文推断:
let color: UInt32 = data.subdata(in: 0..<4).withUnsafeBytes { $0.pointee }
// ...
let lat: Double = data.subdata(in: 8..<16).withUnsafeBytes { $0.pointee }
// ...
随着斯威夫特4,你可以使用下标来提取数据:
let color: UInt32 = data[0..<4].withUnsafeBytes { $0.pointee }
// ...
let lat: Double = data[8..<16].withUnsafeBytes { $0.pointee }
// ...
如果所有字段都将其类型的正确对齐,那么你可以 使用
public func load<T>(fromByteOffset offset: Int = default, as type: T.Type) -> T
从
UnsafeRawPointer
:
data.withUnsafeBytes { (bytes: UnsafePointer<UInt8>) -> Void in
let rawPointer = UnsafeRawPointer(bytes)
let color = rawPointer.load(fromByteOffset: 0, as: UInt32.self)
// ...
let lat = rawPointer.load(fromByteOffset: 8, as: Double.self)
// ...
}
在一个较低的水平,你可以使用memcpy
这又与 任意调整后的数据的工作原理:
var color: UInt32 = 0
var lat: Double = 0
data.withUnsafeBytes { (bytes: UnsafePointer<UInt8>) -> Void in
memcpy(&color, bytes, 4)
// ...
memcpy(&lat, bytes + 8, 8)
// ...
}
我可能会用第一种方法,除非性能是一个 问题,你可以使用第二或第三,这取决于 是否所有字段都保证与其类型对齐。
非常有帮助的回答。数据以网络端序(big endian)存储,因此需要转换为小端。我可以使用“let color = rawPointer.load(fromByteOffset:0,as:UInt32.self).bigEndian”将Uint32值转换为little endian。这种转换不适用于Double。 http://*.com/questions/41161034/how-to-convert-bytes-to-a-float-value-in-swift描述了一种处理转换的方法。这是最简单的吗?我不禁认为这太复杂了,必须有一个更简单的方法。 – pbm
@pbm:你可以先将它读入UInt64(带有endian转换),然后用'Double(bitPattern:...)'将它分配给Double。 - 你如何在C或Java中做到这一点? –