ASP.NET MVC - 将图像上传到Amazon S3

问题描述:

我从Request.Files [0]获得了我的图像。现在,我该如何将这张图片上传到S3?我在AWS .NET API中看到,在放置一个字符串对象时,您必须指定ContentBody。我将如何获取我的文件的内容正文?ASP.NET MVC - 将图像上传到Amazon S3

var file = Request.Files[0]; 
PutObjectRequest request = new PutObjectRequest(); 
request.BucketName = "mybucket" 
request.ContentType = contentType; 
request.Key = key; 
request.InputStream = file.InputStream; 
s3Client.PutObject(request); 
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感谢代码位,也为我解决了一些问题。 – Chaddeus 2010-11-08 04:27:48

很可能这是一个Base64编码的字符串,但您应该检查S3文档以确保它。如果是,则应使用Convert.ToBase64String()并将字节数组传递给它。

下面是一些您可以尝试的示例代码。我没有测试它,但它应该可以帮助您正确的观念:

if (Request.Files.Count >= 1) { 
    var file = Request.Files[0]; 
    var fileContents = new byte[file.ContentLength]; 
    file.InputStream.Read(fileContents, 0, file.ContentLength); 
    var fileBase64String = Convert.ToBase64String(fileContents); 

    // now you can send fileBase64String to the S3 uploader 
} 
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这并不工作,但没有什么工作是使用file.InputStream作为的InputStream的属性PutObjectRequest对象。谢谢你的帮助! – 2010-09-23 19:50:25

与如何使用文件夹和授予所有用户进行只读访问稍微更多的细节。 HTML:

C#

HttpPostedFileBase file = Request.Files[0]; 
    if (file.ContentLength > 0) // accept the file 
     { 
      string accessKey = "XXXXXXXXXXX"; 
      string secretKey = "122334XXXXXXXXXX"; 
      AmazonS3 client; 
      using (client = Amazon.AWSClientFactory.CreateAmazonS3Client(accessKey, secretKey)) 
      { 
       MemoryStream ms = new MemoryStream(); 
       PutObjectRequest request = new PutObjectRequest(); 
     request.WithBucketName("mybucket") 
    .WithCannedACL(S3CannedACL.PublicRead) 
    .WithKey("testfolder/test.jpg").InputStream = file.InputStream; 
     S3Response response = client.PutObject(request); 
      } 

更多详细信息,请访问:http://bradoyler.com/post/3614362044/uploading-an-image-with-aws-sdk-for-net-c

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博客文章是无效链接。 – swbradshaw 2017-11-29 20:07:36

   PurObjectRequest request = new PutObjectRequest() 
       { 
        BucketName = _bucketName, 
        CannedACL = S3CannedACL.PublicRead, 
        Key = string.Format("folderyouwanttoplacethefile/{0}", file.FileName), 
        InputStream = file.InputStream 
       }; 

       YourS3client.PutObject(request); 
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请添加一些关于它如何工作的解释。 – 2016-10-03 20:18:17