推送通知结果87
问题描述:
我在php中发送推送通知我在结果变量中得到了“87”。这是什么意思。推送通知结果87
<?php
$deviceToken = "a448b8946a5de3801dc6a11862a5a0bf11f1adc16xxxxxxxxxxxx"; // masked for security reason
// Passphrase for the private key
$pass = 'molik';
// Get the parameters from http get or from command line
$message = $_GET['message'] or $message = $argv[1] or $message = 'Test Message';
//$badge = (int)$_GET['badge'] or $badge = (int)$argv[2] or $badge = 1;
$sound = $_GET['sound'] or $sound = $argv[3] or $sound = 'default';
// Construct the notification payload
$body = array();
$body['aps'] = array('alert' => $message);
if ($badge)
$body['aps']['badge'] = $badge;
if ($sound)
$body['aps']['sound'] = $sound;
/* End of Configurable Items */
$ctx = stream_context_create();
stream_context_set_option($ctx, 'ssl', 'local_cert', 'ck.pem');
// assume the private key passphase was removed.
stream_context_set_option($ctx, 'ssl', 'passphrase', $pass);
// for production change the server to ssl://gateway.push.apple.com:219
$fp = stream_socket_client('ssl://gateway.sandbox.push.apple.com:2195', $err, $errstr, 60, STREAM_CLIENT_CONNECT, $ctx);
if (!$fp) {
print "Failed to connect $err $errstr\n";
return;
}
else {
print "Connection OK\n";
}
$payload = json_encode($body);
$msg = chr(0) . pack("n",32) . pack('H*', $deviceToken) . pack("n",strlen($payload)) . $payload;
print "sending message :" . $payload . "\n";
$result=fwrite($fp, $msg);
echo ">>" .$result ."<<" . PHP_EOL;
fclose($fp);
输出
Connection OK
sending message :{"aps":{"alert":"Test Message","sound":"default"}}
>>87<<
答
在PHP fwrite
返回写入的字符数,在这种情况下写的套接字的字节数。
输出“>> 87
第三行最后一行回显结果 –
下面的triphoenix是正确的:您收到的数字是由fwrite写入的字节。但是你可以使用它来进行错误检查,因为如果你收到0回应,这意味着fwrite无法写入任何内容,可能是因为Apple关闭了服务器连接。所以它不是带有0响应的fwrite,它是一个先前的成功发送的fwrite,但是苹果不喜欢它,所以它们关闭了服务器连接。如果你在SELECT语句中使用“ORDER BY id”,那么你可以计算出发生问题的地方并从那里继续PUSH。 – jsherk