查找阵列元件具有匹配值
问题描述：
我有一个包含多个对象的阵列，其中一些对象可以具有用于lap_time匹配值，在这个例子元件1，和2具有匹配的值：查找阵列元件具有匹配值
Array
(
[0] => stdClass Object
(
[id] => 1
[recorded_time] => 00:51:55.000000
[corrected_time] => 00:45:32.456140
[lap_time] => 00:09:06.491228
[laps] => 5
[code] =>
[sail_no] => 4931
[class] => SOLO
[helm_fname] => [Removed]
[helm_lname] => [Removed]
[crew_1_fname] =>
[crew_1_lname] =>
[crew_2_fname] =>
[crew_2_lname] =>
[modified_time] =>
[created_time] => 2017-02-19 17:53:48
[created_fname] => Admin
[created_lname] => istrator
[modified_fname] =>
[modified_lname] =>
[points] => 1
)
[1] => stdClass Object
(
[id] => 21
[recorded_time] => 00:50:07.000000
[corrected_time] => 00:45:56.186984
[lap_time] => 00:09:11.237397
[laps] => 5
[code] =>
[sail_no] => 67173
[class] => LASER
[helm_fname] => [Removed]
[helm_lname] => [Removed]
[crew_1_fname] =>
[crew_1_lname] =>
[crew_2_fname] =>
[crew_2_lname] =>
[modified_time] => 2017-02-22 10:51:58
[created_time] => 2017-02-19 18:40:58
[created_fname] => Admin
[created_lname] => istrator
[modified_fname] =>
[modified_lname] =>
[points] => 2
)
[2] => stdClass Object
(
[id] => 2
[recorded_time] => 00:50:07.000000
[corrected_time] => 00:45:56.186984
[lap_time] => 00:09:11.237397
[laps] => 5
[code] =>
[sail_no] => 52441
[class] => LASER
[helm_fname] => [Removed]
[helm_lname] => [Removed]
[crew_1_fname] =>
[crew_1_lname] =>
[crew_2_fname] =>
[crew_2_lname] =>
[modified_time] => 2017-02-22 10:51:58
[created_time] => 2017-02-19 18:40:58
[created_fname] => Admin
[created_lname] => istrator
[modified_fname] =>
[modified_lname] =>
[points] => 3
)
如果任何对象的匹配值为lap_time，匹配对象需要对它们的点进行平均。
这就是我开始做的，但我意识到这可能不是最好的方式去做这件事。 break_race_ties方法尚未完成。
<?php
class Results_calculations_model
{
public
function race_points($results)
{
$points = 0;
$results_with_points = array();
foreach ($results AS $result) {
//increment points by one for each position
$points++;
$result->points = $points;
//add result back to array;
$results_with_points[] = $result;
}
$results_with_points = $this->break_race_ties($results_with_points);
return $results_with_points;
}
protected
function break_race_ties($results)
{
$previous_time = 0;
$ties = array();
foreach ($results AS $result) {
if ($previous_time === $result->lap_time) {
$ties['points'][] = $result->points;
$ties['id'][] = $result->id;
$average_points = $this->average_array_values($ties['points']);
}
$previous_time = $result->lap_time;
}
}
protected
function average_array_values($values)
{
$number_of_elements = count($values);
$total_points = array_sum($values);
return $total_points/$number_of_elements;
}
}
你可以建议可能会帮助我的任何功能，或做什么
答
这里就是我最后做
/**
* Find the amount of points each boat in the race should have
*
* This method will assign points and, in the event of a tie,
* average them.
*
* @param $results
*
* @return array
*/
public function race_points($results)
{
$points = 0;
$results_with_points = array();
//assign incremental amounts of points to each boat
foreach ($results AS $result) {
//increment points by one for each position
$points++;
$result->points = $points;
//add result back to array;
$results_with_points[] = $result;
}
$results_with_points = $this->break_race_ties($results_with_points);
return $results_with_points;
}
/**
* Find any ties and average their points
*
* @param $results
*
* @return mixed
*/
protected function break_race_ties($results)
{
$ties = $this->find_race_ties($results);
if (!empty($ties)) {
//looks like there are tied results, average the points and assign them
foreach ($ties AS $tie) {
$points = $this->average_array_values($tie['points']);
foreach ($tie['id'] AS $id) {
$results[ $id ]->points = $points;
}
}
}
return $results;
}
/**
* Determine if any ties exist and get some information about them
*
* Finds any existing ties in the array of results and gets,
* their element id and the points of each tying boat.
*
* @param $results
*
* @return array
*/
protected function find_race_ties($results)
{
$previous_id = NULL;
$previous_points = NULL;
$previous_time = NULL;
$ties = array();
foreach ($results AS $id => $result) {
if ($previous_time === $result->lap_time) {
// Create empty array if required, so we don't push to NULL
if (!isset($ties[ $previous_time ])) {
$ties[ $previous_time ]['points'] = array();
$ties[ $previous_time ]['id'] = array();
}
// Add each individual value to the array containing duplicates.
// $previous_time is used as a key because it's identical when
// it needs to be, meaning points and ids are grouped.
array_push($ties[ $previous_time ]['points'], $result->points, $previous_points);
array_push($ties[ $previous_time ]['id'], $id, $previous_id);
// Remove duplicate values.
$ties[ $previous_time ]['points'] = array_unique($ties[ $previous_time ]['points']);
$ties[ $previous_time ]['id'] = array_unique($ties[ $previous_time ]['id']);
}
//Set these values for the next iteration to compare against
$previous_id = $id;
$previous_points = $result->points;
$previous_time = $result->lap_time;
}
return $ties;
}
protected function average_array_values($values)
{
$number_of_elements = count($values);
$total_points = array_sum($values);
return $total_points/$number_of_elements;
}
答
的代码示例，试试这个..
class Results_calculations_model
{
public
function race_points($results)
{
$results_with_points = $this->break_race_ties($results);
return $results_with_points;
}
protected
function break_race_ties($results)
{
$previous = null;
foreach($results as &$current) {
if(!empty($previous)) {
$this->average_array_values($current, $previous);
}
$previous = $current;
}
}
protected
function average_array_values(&$current, &$previous)
{
if($current->lap_time == $previous->lap_time) {
$avg = ($current->points + $previous->points)/2;
$current->points = $previous->points = $avg;
}
}
}
如果3个或更多关系出现在单个'lap_time'中，这会起作用吗？ –