PostgreSQL的限制柱至3%的值

问题描述:

SELECT u.id, 
      'Shift' AS which, 
      se.created_at 
    FROM users AS u 
    JOIN schedule_elements AS se ON se.owner_id = u.id 
    UNION ALL 
      (SELECT u.id, 
         'Like' AS which, 
         ll.created_at 
      FROM users AS u 
      JOIN likes AS ll ON ll.owner_id = u.id 
      UNION 
      SELECT u.id, 
         'Comment' AS which, 
         cm.created_at 
      FROM users AS u 
      JOIN comments AS cm ON cm.owner_id = u.id) 
    ORDER BY ID DESC , created_at DESC 


The output looks like: 
id, which, created_at 
555, shift, <date> 
555, shift, <date> 
555, comment, <date> 
555, shift, <date> 
555, like, <date> 
333, shift, <date> 
333, shift, <date> 
333, comment, <date> 
333, shift, <date> 
111, like, <date> 
111, shift, <date> 
111, shift, <date> 

输出具有5个条目ID 555,和4 333我要过滤这个查询,使得我只有顶部3条目555,顶部3 333,等等。PostgreSQL的限制柱至3%的值

使用限制条款https://www.postgresql.org/docs/current/static/queries-limit.html

(SELECT u.id,'Shift' AS which,se.created_at 
    FROM users AS u 
    JOIN schedule_elements AS se ON se.owner_id = u.id ORDER BY u.id DESC , u.created_at DESC LIMIT 3) 
    UNION 
    (SELECT u.id,'Like' AS which,ll.created_at 
    FROM users AS u 
    JOIN likes AS ll ON ll.owner_id = u.id ORDER BY u.id DESC , u.created_at DESC LIMIT 3) 
    UNION 
    (SELECT u.id,'Comment' AS which,cm.created_at 
    FROM users AS u 
    JOIN comments AS cm ON cm.owner_id = u.id ORDER BY u.id DESC , u.created_at DESC LIMIT 3) 
+0

看起来像这个查询不会工作 - 你可以使用LIMIT只用于整个语句(所有3联合)。甚至它的作品,它会显示每个SELECT 3项目不是所有。 –

+0

看起来像它在这里工作http://*.com/questions/1415328/combining-union-and-limit-operations-in-mysql-query – pottedmeat7

+0

这是完全不同的任务。每两家不同的公司需要10条记录。在这里 - 最后3次对用户+他们的评论和喜欢的操作。 –

也许你需要的是这样的。对于CTE中的p,我使用您的查询。在p2中,我通过窗口函数为所有行设置了row_number,之后每个用户只能显示第一个/最后一个3。

WITH p AS (
    SELECT u.id, 
      'Shift' AS which, 
      se.created_at 
    FROM users AS u 
    JOIN schedule_elements AS se ON se.owner_id = u.id 
    UNION ALL 
    SELECT u.id, 
      'Like' AS which, 
      ll.created_at 
    FROM users AS u 
    JOIN likes AS ll ON ll.owner_id = u.id 
    UNION ALL 
    SELECT u.id, 
     'Comment' AS which, 
     cm.created_at 
    FROM users AS u 
    JOIN comments AS cm ON cm.owner_id = u.id 
), p2 AS (
    SELECT *, 
     row_number() OVER (PARTITION BY id ORDER BY created_at DESC) AS rank 
    FROM p 
    WHERE which IS NOT NULL 
) 
SELECT id, which, created_at --, rank 
FROM p2 
WHERE rank <= 3 
ORDER BY ID DESC , created_at DESC; 
+0

如果我的回答对您有帮助,请将您的问题标记为已解决并投票给我。谢谢 –