在时间上发送多个模拟器短信
问题描述:
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我开发一个Android应用程序,我需要发送一条消息给 在同一时间。但问题是只有一个 仿真器接收message.Here接收多个模拟器是我的代码。在时间上发送多个模拟器短信
公共类SMS延伸活动 {
/** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); btnSendSMS = (Button) findViewById(R.id.btn_SendSms); txtPhoneNo = (EditText) findViewById(R.id.edittext_PhoneNumber); txtMessage = (EditText) findViewById(R.id.edittext_MessageBody); btnSendSMS.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { String message = txtMessage.getText().toString(); String phoneNo = txtPhoneNo.getText().toString(); StringTokenizer st=new StringTokenizer(phoneNo,","); while (st.hasMoreElements()) { String tempMobileNumber = (String)st.nextElement(); if(tempMobileNumber.length()>0 && message.trim().length()>0) { sendSMS(tempMobileNumber, message); } else { Toast.makeText(getBaseContext(), "Please enter both phone number and message.", Toast.LENGTH_SHORT).show(); } } } }); } private void sendSMS(String phoneNumber, String message) { String SENT = "SMS_SENT"; String DELIVERED = "SMS_DELIVERED"; PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0); PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0); //---when the SMS has been sent--- registerReceiver(new BroadcastReceiver() { @Override public void onReceive(Context arg0, Intent arg1) { switch (getResultCode()) { case Activity.RESULT_OK: Toast.makeText(getBaseContext(), "SMS sent", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_GENERIC_FAILURE: Toast.makeText(getBaseContext(), "Generic failure", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_NO_SERVICE: Toast.makeText(getBaseContext(), "No service", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_NULL_PDU: Toast.makeText(getBaseContext(), "Null PDU", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_RADIO_OFF: Toast.makeText(getBaseContext(), "Radio off", Toast.LENGTH_SHORT).show(); break; } } } , new IntentFilter(SENT)); SmsManager sms = SmsManager.getDefault(); sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI); } }
答
您可以创建仿真器ID或编号的数组,然后将sendTextMessage插入到执行该循环的许多元素到数组中。或者您可以有UI,允许用户将电话号码或模拟器号码插入到列表中,并按照上述相同的步骤进行操作! 注意sendTextMessage单曲第一说法是“电话号码”您要发送短信 只需用您的要求为每一个重复循环替换谁