如何在启动设备时启动应用程序?
答
此代码将在启动时启动应用程序。你需要听取ACTION_BOOT_COMPLETE。
in AndroidManifest.xml (application-part):
<receiver android:enabled="true" android:name=".BootUpReceiver"
android:permission="android.permission.RECEIVE_BOOT_COMPLETED">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</receiver>
[..]
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
[..]
public class BootUpReceiver extends BroadcastReceiver{
@Override
public void onReceive(Context context, Intent intent) {
Intent i = new Intent(context, MyActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
}
+0
感谢您的帮助:) – piks 2011-12-29 12:56:02
精确复制http://*.com/questions/6391902/how-to-start-an-application-on-startup – 2011-12-28 10:47:50