图片上传到服务器在android
问题描述:
我有一些问题之前,我解决了。感谢所有回答问题的人。图片上传到服务器在android
我想从我的android应用程序上传图像到服务器(Servelet)。我也模拟了包含一个jpeg图像的SD卡。
我已经能够与服务器建立连接并获得一些消息。但到目前为止,我还没有能够检索服务器上的图像。我在服务器上收到错误消息。我正在使用多部分选项。代码如下。 Plz看看,让我知道我在做什么错。
ANDROID SIDE
String path="http://10.0.2.2:8080/ImageLocalizer/Localize";
String pathToFile="/sdcard/building.jpg";
text1.setText(path);
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
try
{
FileInputStream fileInputStream = new FileInputStream(new File(pathToFile));
URL url = new URL(path);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
// Allow Inputs & Outputs
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
// Enable POST method
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data");
connection.setRequestProperty("FileName", "building.jpg");
DataOutputStream outputStream =new DataOutputStream(connection.getOutputStream());
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
fileInputStream.close();
outputStream.flush();
outputStream.close();
text1.setText(path);
BufferedReader in =new BufferedReader(new InputStreamReader(connection.getInputStream()));
String response="",msg="";
while ((response = in.readLine()) != null) {
msg+=response;
}
text2.setText(msg);
}
catch (Exception ex)
{}
}
小服务程序SIDE
doPost()
{
System.out.println("RUNNING");
InputStream in = request.getInputStream();
BufferedReader r = new BufferedReader(new InputStreamReader(in));
StringBuffer buf = new StringBuffer();
String line;
PrintWriter out = response.getWriter();
out.println("Image copied !!");
out.close();
try
{
PrintWriter out1=response.getWriter();
FileItemFactory factory = new DiskFileItemFactory();
ServletFileUpload upload = new ServletFileUpload(factory);
String s[]=new String[30];
byte i=0;
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
if(isMultipart)
{
List items=upload.parseRequest(request);
Iterator iterator=items.iterator();
while(iterator.hasNext())
{
FileItem fitem=(FileItem)iterator.next();
if(!fitem.isFormField())
{
StringBuffer s2=new StringBuffer(fitem.getName());
if(s2!=null && s2.length()>0)
{
File fl=new File("H:\\abcd.jpg");
fitem.write(fl);
}
}
if(fitem.isFormField())
{
s[i]=fitem.getString();
i++;
}
}
}
}catch(Exception e){e.printStackTrace();}
}
答
我不认为你的请求主体的格式修正为多部分表单数据。正文应该包含几个不同的分隔部分,每部分包含该部分的文件名和编码。请参阅以下网址为例:
http://chxo.com/be2/20050724_93bf.html
如果你只发布在一个时间我会删除多部分表单数据头和刚刚发布的文件作为请求正文的内容,一个文件。
字节读取方法怎么样?以字节形式发送图像? – user1388142
我不确定我是否理解您的评论,但您可以将图像作为字节发送并直接在服务器上读取这些字节。这意味着你没有发送多部分表单,所以你应该删除该表头。 –