C程序存储文件锯齿阵列和排序它
我想创建C程序来读取文本文件并按升序排序。文本文件的例子是C程序存储文件锯齿阵列和排序它
2
3; 2, 5, 7
6; 4, 7, 8, 9, 5, 2
用第一行表示的行数,数字后的“;”指示元素的每行和元素用“,”分隔。 所以我的想法是创建一个动态锯齿阵列作为第一个数字的行,然后指出每个行与元素不同的数组。首先对指针数组排序,然后对每个数组的元素进行排序这是我迄今
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int SortLists();
int main()
{
int i,j = 0;
char filename[10]; //name of the file
char line[100];
int rows = 3; //I have to initialized this to test my code first
int cols;
int **jaggedArr; //jagged array
jaggerArr = malloc (rows*sizeof(int*)) ;
printf("Enter the file name with .txt : ");
scanf("%s", filename);
FILE *filePtr = fopen(filename, "r");
int num;
if (filePtr != NULL)
{
while (fgets(line, sizeof(line), filePtr) != NULL) //read each line of the text
{
cols = atoi(strtok(line, ";")); //use strtk to break elements
for (i = 0; i < rows; i++)
{
for (j = 0; j < cols; j++)
{
jaggedArr[i][j] = atoi(strtok(line, ",")); //parse into the jagged array
}
}
}
fclose(filePtr);
}
}
int SortLists(int list[], int size) //sort method
{
int i,j,temp;
for (i = 0; i < size; ++i)
{
for (j = i + 1; j < size; ++j)
{
if (list[i] > list[j])
{
temp = list[i];
list[i] = list[j];
list[j] = temp;
}
}
}
}
试图同C初学者,我不熟悉指针的想法,这与C#有很多不同。 对不起,我的英语不好,因为它不是我的第一语言。非常感谢你帮助我。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define S_(x) #x
#define S(x) S_(x)
void SortLists(int list[], int size);
int main(void){
char filename[FILENAME_MAX+1];
char line[100];
int rows, cols;
printf("Enter the file name with .txt : ");
scanf("%" S(FILENAME_MAX) "[^\n]%*c", filename);
FILE *filePtr = fopen(filename, "r");
if(!filePtr)
return EXIT_FAILURE;
fscanf(filePtr, "%d ", &rows);
int **jaggedArr;
jaggedArr = malloc (rows * sizeof(int*));
int *sizeArr = malloc(rows * sizeof(int));
int r = 0, c;
while (fgets(line, sizeof(line), filePtr) != NULL){
sizeArr[r] = cols = atoi(strtok(line, ";"));
jaggedArr[r] = malloc(cols * sizeof(int));
for (c = 0; c < cols; ++c){
jaggedArr[r][c] = atoi(strtok(NULL, ","));
}
SortLists(jaggedArr[r++], cols);
}
fclose(filePtr);
//check print and deallocation
for(r = 0;r < rows; ++r){
for(c = 0; c < sizeArr[r]; ++c)
printf("%d ", jaggedArr[r][c]);
printf("\n");
free(jaggedArr[r]);
}
free(jaggedArr);
free(sizeArr);
return 0;
}
void SortLists(int list[], int size){
int i,j,temp;
for (i = 0; i < size-1; ++i){
for (j = i + 1; j < size; ++j){
if (list[i] > list[j]){
temp = list[i];
list[i] = list[j];
list[j] = temp;
}
}
}
}
谢谢你帮助我。请问,'fscanf'(filePtr,“%d”,&rows);''获得文本的行号,因为它是文本文件中的第一个数字吗?另外,什么是指针'* sizeArr'呢?尝试使用文本文件运行你的代码,但它的工作不正常,所以这里一定缺少一些东西 – user4075830 2014-09-24 18:38:46
@ user4075830 _it是文本文件中的第一个数字_是的_什么是指针* sizeArr的做法?_你需要保持大小因为每一行的大小不同 – BLUEPIXY 2014-09-24 18:51:28
@ user4075830 [DEMO](http://ideone.com/9GFx54) – BLUEPIXY 2014-09-24 18:55:49
对于额外的问题。
#include <stdio.h>
void SortLists(int list[], int size);
void SortRows(int *jaggedArr[], int size, int *rowSize);
int main(void){
int row1[] = {4,7,8,9,5,2};
int row2[] = {2,5,7};
int *jaggedArr[] = { row1, row2};
int rows = 2;
int sizeArr[] = {6,3};
int i, r, c;
for(i=0;i<rows;++i)
SortLists(jaggedArr[i], sizeArr[i]);
for(r = 0;r < rows; ++r){
for(c = 0; c < sizeArr[r]; ++c)
printf("%d ", jaggedArr[r][c]);
printf("\n");
}
printf("\n");
SortRows(jaggedArr, rows, sizeArr);
for(r = 0;r < rows; ++r){
for(c = 0; c < sizeArr[r]; ++c)
printf("%d ", jaggedArr[r][c]);
printf("\n");
}
return 0;
}
void SortLists(int list[], int size){
int i,j,temp;
for (i = 0; i < size-1; ++i){
for (j = i + 1; j < size; ++j){
if (list[i] > list[j]){
temp = list[i];
list[i] = list[j];
list[j] = temp;
}
}
}
}
void SortRows(int *jaggedArr[], int size, int *rowSize){
int i,j,temp,*tempp;
for (i = 0; i < size-1; ++i){
for (j = i + 1; j < size; ++j){
if (rowSize[i] > rowSize[j]){
//swap in pairs
temp = rowSize[i];
rowSize[i] = rowSize[j];
rowSize[j] = temp;
tempp = jaggedArr[i];
jaggedArr[i] = jaggedArr[j];
jaggedArr[j] = tempp;
}
}
}
}
#include <stdio.h>
void SortLists(int list[], int size);
void SortRows(int *jaggedArr[], int size);
int main(void){
int row1[] = {6, 4,7,8,9,5,2};//The first element represents the number of elements.
int row2[] = {3, 2,5,7};
int *jaggedArr[] = { row1, row2};
int rows = 2;
//int sizeArr[] = {6,3};//Not required
int i, r, c;
for(i=0;i<rows;++i)
SortLists(jaggedArr[i]+1, jaggedArr[i][0]);
SortRows(jaggedArr, rows);
for(r = 0;r < rows; ++r){
for(c = 1; c <= jaggedArr[r][0]; ++c)
printf("%d ", jaggedArr[r][c]);
printf("\n");
}
return 0;
}
void SortLists(int list[], int size){
int i,j,temp;
for (i = 0; i < size-1; ++i){
for (j = i + 1; j < size; ++j){
if (list[i] > list[j]){
temp = list[i];
list[i] = list[j];
list[j] = temp;
}
}
}
}
void SortRows(int *jaggedArr[], int size){
int i,j,*tempp;
for (i = 0; i < size-1; ++i){
for (j = i + 1; j < size; ++j){
if (jaggedArr[i][0] > jaggedArr[j][0]){
tempp = jaggedArr[i];
jaggedArr[i] = jaggedArr[j];
jaggedArr[j] = tempp;
}
}
}
}
反复'的strtok(行 “”)'不会做你想做的。由';'分隔的开启者看起来很有希望,但是行处理的其余部分应该用'strtok(NULL,',')'完成。也许为这些行分配一些*内存* – WhozCraig 2014-09-24 17:19:04
感谢您花时间回答我的问题。通过分配内存,你的意思是使用行中元素的数量来初始化数组的大小? – user4075830 2014-09-24 17:54:08