合并与第二组对象的Javascript数组和组
问题描述:
我有两个对象数组。一个数组包含项目列表,另一个数组包含类别列表。我想创建一个基于categoryIds的新数组。我尝试使用lodash。但是,无法得到正确的解决方案。合并与第二组对象的Javascript数组和组
我可以使用循环来做到这一点。但是,我正在寻找更干净的方法。
var items = [
{
id: '001',
name: 'item1',
description: 'description of item1',
categoryId: 'cat1'
},
{
id: '002',
name: 'item2',
description: 'description of item2',
categoryId: 'cat2'
},
{
id: '003',
name: 'item3',
description: 'description of item3',
categoryId: 'cat1'
},
{
id: '004',
name: 'item4',
description: 'description of item4'
}
];
var categories = [
{
id: 'cat1',
name: 'Category1'
},
{
id: 'cat2',
name: 'Category2'
}
];
预计输出
[
{
categoryId: 'cat1',
name: 'Category1',
items: [
{
id: '001',
name: 'item1',
description: 'description of item1',
categoryId: 'cat1'
},
{
id: '003',
name: 'item3',
description: 'description of item3',
categoryId: 'cat1'
}
]
},
{
categoryId: 'cat2',
name: 'Category2',
items: [
{
id: '002',
name: 'item2',
description: 'description of item2',
categoryId: 'cat2'
}
]
},
{
categoryId: '',
name: '',
items: [
{
id: '004',
name: 'item4',
description: 'description of item4'
}
]
}
]
https://jsfiddle.net/sfpd3ppn/
感谢您的帮助
答
可以完成使用reduce期望的结果。我们将从原始categories
阵列开始,并将其中的items
阵列减少。
var items = [
{ id: '001', name: 'item1', description: 'description of item1', categoryId: 'cat1' },
{ id: '002', name: 'item2', description: 'description of item2', categoryId: 'cat2' },
{ id: '003', name: 'item3', description: 'description of item3', categoryId: 'cat1' },
{ id: '004', name: 'item4', description: 'description of item4' }
];
var categories = [
{ id: 'cat1', name: 'Category1' },
{ id: 'cat2', name: 'Category2' }
];
// Lets add the empty category at the beginning. This simplifies the logic.
categories.push({ id: '', name: '' });
// This is a function that will return a function to be used as a filter later on
function createFilter (category) {
return function (item) {
return item.id === category;
};
}
var mergedSet = items.reduce(function (previous, current) {
// Get the category ID of the current item, if it doesn't exist set to empty string
var categoryId = current.categoryId || '';
// Find the cateogry that matches the category ID
var category = previous.find(createFilter(categoryId));
// If the items property doesn't exists (we don't have any items), create an empty array
if (!category.items) { category.items = []; }
// Add the item the category
category.items.push(current);
// Return the current value that will be used in the next iteration.
// Note, the initial value of previous will be the intial value of categories.
return previous;
}, categories);
console.log(mergedSet);
/* Output
[
{ id: 'cat1',
name: 'Category1',
items:
[ { id: '001',
name: 'item1',
description: 'description of item1',
categoryId: 'cat1' },
{ id: '003',
name: 'item3',
description: 'description of item3',
categoryId: 'cat1' }
]
},
{ id: 'cat2',
name: 'Category2',
items:
[ { id: '002',
name: 'item2',
description: 'description of item2',
categoryId: 'cat2'
}
]
},
{ id: '',
name: '',
items:
[ { id: '004',
name: 'item4',
description: 'description of item4' } ] }
]
*/
答
下面的伎俩:
var items = [{ id: '001', name: 'item1', description: 'description of item1', categoryId: 'cat1' }, { id: '002', name: 'item2', description: 'description of item2', categoryId: 'cat2' }, { id: '003', name: 'item3', description: 'description of item3', categoryId: 'cat1' }, { id: '004', name: 'item4', description: 'description of item4' } ];
var categories = [ { id: 'cat1', name: 'Category1' }, { id: 'cat2', name: 'Category2' } ];
var output = categories.concat([{id:'',name:''}]).map(function(v) {
return {
categoryId: v.id,
name: v.name,
items: items.filter(function(o) {
return o.categoryId === v.id || !o.categoryId && !v.id;
})
};
});
console.log(output);
我用.concat()
创建一个新的类别数组保存原始categories
项目加上一个“空”类别开始。然后,我.map()
该数组返回类别对象与您所需的输出结构,其中每个具有items
阵列由.filter()
数组生成的原始items
数组。
(注意:output
内items
阵列包含对在原始items
输入相同的对象,不是他们的副本引用。如果你想拷贝你可以在.filter()
后再添.map()
。)
答
假设变量categories
和items
如你在上面定义的分配:
const keyedCategories = _(categories)
.concat({ id: '', name: '' })
.keyBy('id')
.value();
const groupedItems = _.groupBy(items, (item) => _.get(item, 'categoryId', ''));
const result = _.reduce(groupedItems, (acc, value, key) => {
const { id: categoryId, name } = keyedCategories[key];
return _.concat(acc, { categoryId, name, items: value });
}, []);
* - 哪里是你的企图:“我可以用循环做到这一点。”?你的小提琴只包括输入对象和所需的输出。 – nnnnnn
对不起。我已经更新了jsfiddle。请看一看。 https://jsfiddle.net/sfpd3ppn/1/ – jintoppy