拖放项目放在UIStackView
问题描述:
我有下面的代码,并需要拖动视图,以便他们可以重新定位。但是,拖动时,视图就会消失。如何在堆栈视图之上使视图可拖动?拖放项目放在UIStackView
堆栈视图:
let sView = UIStackView()
sView.axis = UILayoutConstraintAxis.Vertical
sView.distribution = .FillEqually
sView.alignment = UIStackViewAlignment.Center
sView.spacing = 15
sView.backgroundColor = UIColor.redColor()
sView.addArrangedSubview(view1)
sView.addArrangedSubview(view2)
sView.addArrangedSubview(view3)
sView.layoutMarginsRelativeArrangement = true
sView.translatesAutoresizingMaskIntoConstraints = false
self.view.addSubview(sView)
sView.centerXAnchor.constraintEqualToAnchor(self.view.centerXAnchor).active = true
sView.centerYAnchor.constraintEqualToAnchor(self.view.centerYAnchor).active = true
的意见; view1
,view2
,并view3
有如下类似的代码:
let view1 = UIView()
view1.frame = CGRectMake(30, 50, 50, 80)
view1.backgroundColor = UIColor.blueColor()
view1.layer.cornerRadius = 6
let gesture = UIPanGestureRecognizer(target: self, action: Selector("draggedView:"))
view1.addGestureRecognizer(gesture)
view1.userInteractionEnabled = true
view1.tag = 1
view1.heightAnchor.constraintEqualToConstant(85).active = true
view1.widthAnchor.constraintEqualToConstant(55).active = true
的draggedView
功能:
func draggedView(gesture: UIPanGestureRecognizer){
let loc = gesture.locationInView(self.view)
let gesturedView = gesture.view
gesturedView!.center = loc
}
答
布赖恩,
此代码做什么,我想你希望做。显然你需要仔细考虑并更改变量名称,但我相信你会接受它!
func draggedView(sender: UIPanGestureRecognizer) {
if (sender.state == UIGestureRecognizerState.Began) {
self.source = editorSVB!.arrangedSubviews.indexOf(sender.view!)! as Int
}
if (sender.state == UIGestureRecognizerState.Changed) {
center = sender.view?.center
let translation = sender.translationInView(sender.view)
center = CGPointMake(center!.x + translation.x, center!.y + translation.y)
sender.view?.center = center!
sender .setTranslation(CGPointZero, inView: sender.view)
}
for blah in self.editorSVB!.arrangedSubviews {
let no = blah.frame.intersect((sender.view?.frame)!)
if (!no.origin.x.isInfinite) {
self.object = editorSVB!.arrangedSubviews.indexOf(blah)! as Int
if (self.object != self.source) {
print("self,object, self.object",self,object, self.source)
self.executable = self.object
}
}
}
}
+0
谢谢你,你的代码更简单和有效。 – Kawalya
+0
Kawalya,如果您使用它,请将其标记为已接受的答案! – user3069232
嗨,你有一个更简单的问题答案? – Kawalya
下面给出的答案工作正常。 – Kawalya