异步数组函数

问题描述:

所以我有一个四个JSON对象的数组,我想向这些对象中的每个添加三个新的字段。为此,我需要为每个要添加的新字段设置一个异步函数。理想情况下,我想要做的是将异步函数限制为每次只更新两次。最后,回调原始函数并打印出新形成的数组。但我不能得到这个工作,虽然我觉得我靠近......异步数组函数

var async = require('async'); 

// My Array of JSON objects 
var allIssues = [ 
    { id: '1', color: 'blue' }, 
    { id: '2', color: 'red' }, 
    { id: '3', color: 'gold' } 
]; 

addExtraFeaturesToEachissue(allIssues, function(data) { console.log(data); }); 

function addExtraFeaturesToEachissue(allIssues, callback) { 
    async.each(
     allIssues, 
     async.applyEach([addheight, addWidth, addWeight]), 
     callback(data) 
    ); 
} 

function addHeight(issue, callback) { 
    setTimeout(function() { 
     issue.fields['height'] = "1000"; 
     callback(issue); 
    }, 100); 
} 
function addWidth(issue, callback) { 
    setTimeout(function() { 
     issue['width'] = "100"; 
     callback(issue); 
    }, 300);  
} 
function addWeight(issue, callback) { 
    setTimeout(function() { 
     issue.['weight'] = "500"; 
     callback(issue); 
    }, 200); 
} 
+0

请包括预期的JSON数组的形状。另外,为什么你选择异步方法并延迟使用超时填充JSON数组? –

+0

[ {id:'1',color:'blue','width':100,'weight':'500',height:'1000'}, {id:'2',color:'red' ,'宽度':100,'重量':'500',高度:'1000}, {id:'3',颜色:'gold','width':100'weight':'500' :'1000} ]; 他们区域实际上更复杂的功能,我只是把一个随机计时器,以表明他们需要一段时间来执行 –

假设调用的函数会做一些长期的任务,老实说,我不认为使用异步的需要,为什么不使用Promise?

// My Array of JSON objects 
var allIssues = [ 
    { id: '1', color: 'blue' }, 
    { id: '2', color: 'red' }, 
    { id: '3', color: 'gold' } 
]; 

addExtraFeaturesToEachissue(allIssues, function(data) { console.log(data); }); 

function addExtraFeaturesToEachissue(allIssues, callback) { 
    var requests = allIssues.map((issue) => { 
    return addHeight(issue).then(addWidth).then(addWeight); 
    }); 
    Promise.all(requests).then((data) => console.log('done', data)); 
} 

function addHeight(issue) { 
    return new Promise((resolve, reject) => { 
    setTimeout(function() { 
     issue.height = "1000"; 
     resolve(issue); 
    }, 100); 
}); 
} 
function addWidth(issue) { 
    return new Promise((resolve, reject) => { 
    setTimeout(function() { 
     issue.width = "100"; 
     resolve(issue); 
    }, 300); 
    }); 
} 
function addWeight(issue) { 
    return new Promise((resolve, reject) => { 
    setTimeout(function() { 
     issue.weight = "500"; 
     resolve(issue); 
    }, 200); 
    }); 
} 

编辑我刚看到你whant末,整个阵列。正如Jared Smith所建议的那样,您可以使用Promise.all;)

+0

看看'Promise.all' ... –